Introduction for double exponential function:
Standard form of exponential functions is in the form of f(x) = `b^(b^x),` here b is the number greater than zero and x is the exponent. Here the value of x is given we need to find the exponential functions. For example f(x) = `2^(2^x)` when the value of x is 4 we need to substitute the value in the 4 in the x place and find the double exponential functions of f(4) = `(2^2)^4` .By using the standard form of exponential function we will discuss some important problems in the below concepts.
Problem in Double Exponential Function:
Simplify the double exponential functions.
Problem (i) Find the double exponential function of f(x) = `4^(4^x)` here x is 3
Solution: Substitute the x values exponential function
f(x) = `4^(4^x)`
f(3) = `4^(4^3)` substitute the x value 3 in the functions.
f(3) =` 4^(4^3)` .
f(3) = 464. here 43 is 64
f(3) = 3.40282367x1038
Problem (ii) Find the double exponential function of f(x) = `5^(5^x)` here x is 2
Solution: Substitute the x values in the standard form of exponential function
f(x) = `5^(5^x)`
f(2) = `5^(5^2) ` substitute the x value 2 in the functions.
f(2) = `5^(5^2).`
f(2) = 525. in this step 52 is 25
f(2) = 2.98023224x1017
Problem (iii) Find the double exponential function of f(x) = `8^(8^x)` here x is 1
Solution: Substitute the x values in the standard form of exponential function
f(x) = `8^(8^1)`
f(1) = `8^(8^1)` substitute the x value 3 in the functions.
f(1) = 88 here 81 is 8.
f(1) = 88.
f(1) = 16777216. I have recently faced lot of problem while learning The Coordinate Plane, But thank to online resources of math which helped me to learn myself easily on net.
Problem Double Exponential Functions:
Simplify the standard form of exponential functions.
Problem (i) Find the double exponential function of f(x) =` 19^(19^x)` here x is 0
Solution: Substitute the x values in the standard form of exponential function
f(x) = `19^(19^x)`
f(0) =` 19^(19^0)` substitute the x value 0 in the functions.
f(0) = 191 in this step anything power zero is 1.
f(0) = 19.
Problem (ii) Find the double exponential function of f(x) = `25^(25^x)` here x is 1
Solution: Substitute the x values in the standard form of exponential function
f(x) = `25^(25^x)`
f(1) = `25^(25^1)` substitute the x value 1 in the functions.
f(1) = 2525.
f(1) =2525 = 8.8817842 × 1034
Standard form of exponential functions is in the form of f(x) = `b^(b^x),` here b is the number greater than zero and x is the exponent. Here the value of x is given we need to find the exponential functions. For example f(x) = `2^(2^x)` when the value of x is 4 we need to substitute the value in the 4 in the x place and find the double exponential functions of f(4) = `(2^2)^4` .By using the standard form of exponential function we will discuss some important problems in the below concepts.
Problem in Double Exponential Function:
Simplify the double exponential functions.
Problem (i) Find the double exponential function of f(x) = `4^(4^x)` here x is 3
Solution: Substitute the x values exponential function
f(x) = `4^(4^x)`
f(3) = `4^(4^3)` substitute the x value 3 in the functions.
f(3) =` 4^(4^3)` .
f(3) = 464. here 43 is 64
f(3) = 3.40282367x1038
Problem (ii) Find the double exponential function of f(x) = `5^(5^x)` here x is 2
Solution: Substitute the x values in the standard form of exponential function
f(x) = `5^(5^x)`
f(2) = `5^(5^2) ` substitute the x value 2 in the functions.
f(2) = `5^(5^2).`
f(2) = 525. in this step 52 is 25
f(2) = 2.98023224x1017
Problem (iii) Find the double exponential function of f(x) = `8^(8^x)` here x is 1
Solution: Substitute the x values in the standard form of exponential function
f(x) = `8^(8^1)`
f(1) = `8^(8^1)` substitute the x value 3 in the functions.
f(1) = 88 here 81 is 8.
f(1) = 88.
f(1) = 16777216. I have recently faced lot of problem while learning The Coordinate Plane, But thank to online resources of math which helped me to learn myself easily on net.
Problem Double Exponential Functions:
Simplify the standard form of exponential functions.
Problem (i) Find the double exponential function of f(x) =` 19^(19^x)` here x is 0
Solution: Substitute the x values in the standard form of exponential function
f(x) = `19^(19^x)`
f(0) =` 19^(19^0)` substitute the x value 0 in the functions.
f(0) = 191 in this step anything power zero is 1.
f(0) = 19.
Problem (ii) Find the double exponential function of f(x) = `25^(25^x)` here x is 1
Solution: Substitute the x values in the standard form of exponential function
f(x) = `25^(25^x)`
f(1) = `25^(25^1)` substitute the x value 1 in the functions.
f(1) = 2525.
f(1) =2525 = 8.8817842 × 1034
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